document.write( "Question 994199: The perimeter of a rectangle is 210 feet. Describe the possible lengths of a side if the area of the rectangle is not to exceed 2250 square feet.\r
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document.write( "Your answer should be one interval in each box.\r
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document.write( "ANSWER: The length (in feet) of a side is in the interval....???
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document.write( " or in the interval....???
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Algebra.Com's Answer #613400 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The perimeter of a rectangle is 210 feet. Describe the possible lengths of a side if the area of the rectangle is not to exceed 2250 square feet. \n" ); document.write( "Your answer should be one interval in each box. \n" ); document.write( "ANSWER: The length (in feet) of a side is in the interval....??? \n" ); document.write( "or in the interval....??? \n" ); document.write( "----- \n" ); document.write( "length + width = 105 \n" ); document.write( "length * width <= 2250 \n" ); document.write( "------ \n" ); document.write( "Substitute for \"length\" and solve for \"width\":: \n" ); document.write( "(105-width)*width <= 2250 \n" ); document.write( "---- \n" ); document.write( "-w^2 + 105w - 2250 <= 0 \n" ); document.write( "------ \n" ); document.write( "w^2 - 105w + 2250 >= 0 \n" ); document.write( "------ \n" ); document.write( "Equality:: \n" ); document.write( "width = 30 or 75 \n" ); document.write( "---- \n" ); document.write( "If width < 30, then length is > 75 \n" ); document.write( "If width > 30, then lenght is < 75 \n" ); document.write( "----------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |