document.write( "Question 994173: The length of a rectangle is 4in. Greater than its width. The perimeter of the rectangle is 24in. Find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "W=width l=length\r
\n" ); document.write( "\n" ); document.write( "I know that to find the length it's 4+w(2)
\n" ); document.write( "I know that the width would be 2w
\n" ); document.write( "I just need help checking and I'm wondering if I'm missing anything
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Algebra.Com's Answer #613384 by macston(5194)\"\" \"About 
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\n" ); document.write( "W=width; L=length=W+4
\n" ); document.write( ".
\n" ); document.write( "P=2(L+W)
\n" ); document.write( "24in=2((W+4)+W)
\n" ); document.write( "12in=2W+4
\n" ); document.write( "8in=2W
\n" ); document.write( "4in=W
\n" ); document.write( "ANSWER 1: The width is 4 inches.
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\n" ); document.write( "L=W+4
\n" ); document.write( "L=4+4=8
\n" ); document.write( "ANSWER 2: The length is 8 inches.
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\n" ); document.write( "CHECK:
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\n" ); document.write( "P=2(L+W)
\n" ); document.write( "24in=2(8in+4in)
\n" ); document.write( "24in=2(12in)
\n" ); document.write( "24in=24in
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