document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994150>Question 994150</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that one solution contains 50% alcohol and the other solution contains 80% alcohol. How many liters of each solution should be mixed to make 10.5 of a 70% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613360 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613360\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose that one solution contains 50% alcohol and the other solution contains 80% alcohol. How many liters of each solution should be mixed to make 10.5 of a 70% solution? <BR>\n" );
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document.write( "Equation::<BR>\n" );
document.write( "alcohol + alcohol = alcohol<BR>\n" );
document.write( "0.50x + 0.80(10.5-x) = 0.70*10.5<BR>\n" );
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document.write( "50x + 80*10.5 - 80x = 70*10.5<BR>\n" );
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document.write( "-30x = -10*10.5<BR>\n" );
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document.write( "x = (1/3)10.5<BR>\n" );
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document.write( "x = 3.5 liters (amt. of 50% solution needed)<BR>\n" );
document.write( "10.5-x = 7 liters (amt. of 80% solution needed)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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