document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994132>Question 994132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the general formula for (-1/4, 2/9, -3/16, 4/25,...)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613353 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613353\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> looks like the formula is x divided by (x+1)^2 * (-1)^2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "when x = 1, the term is 1/2^2 * (-1)^1 = -1/4\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "when x = 2, the term is 2/3^2 * (-1)^2 = 2/9\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "whehn x = 3, the term is 3/4^2 * (-1)^3 = -3/16\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "when x = 4, the term is 4/5^2 * (-1)^4 = 4/25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );