document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994130>Question 994130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the denominator of a fraction exceeds its numerator by 3. if the numerator is decreased by 1 and the denominator is increased by 3, the value of the resulting fraction is 1/2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613349 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613349\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x-1) / (x+6) = 1/2\r<BR>\n" );
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document.write( "multiply both sides of this equation by (x+6) to get:\r<BR>\n" );
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document.write( "(x-1) = 1/2 * (x + 6)\r<BR>\n" );
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document.write( "multiply both sides of this equation by 2 to get:\r<BR>\n" );
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document.write( "2x-1 = x+6\r<BR>\n" );
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document.write( "add 1 to both sides of this equation and subtract x from both sides of this equation to get:\r<BR>\n" );
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document.write( "2x - x = 6 + 1\r<BR>\n" );
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document.write( "combine like terms to get:\r<BR>\n" );
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document.write( "x = 7\r<BR>\n" );
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document.write( "when x = 7, (x-1) / (x+6) becomes 7/14 which is equal to 1/2.\r<BR>\n" );
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document.write( "the original fraction of x / (x+3) must be equal to 8 / 11.\r<BR>\n" );
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document.write( "subtract 1 from the numerator of 8 and you get 7.<BR>\n" );
document.write( "add 3 to the denominator of 11 and you get 14.\r<BR>\n" );
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document.write( "if i understood what you are looking for, the solution appears to be x = 8.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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