document.write( "Question 994117: Please help me solve this question\r
\n" ); document.write( "\n" ); document.write( "If x2 - 2y2 = 7 and xy = 3 , find x and y\r
\n" ); document.write( "\n" ); document.write( "Note : the number 2 behind x and 2y means squared \r
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Algebra.Com's Answer #613332 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "\"system%28x%5E2+-+2y%5E2+=+7%2C%0D%0Axy+=+3%29\".\r
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\n" ); document.write( "\n" ); document.write( "Express y from the second equation,  y = \"3%2Fx\",  and substitute it into the first equation.  You will get single equation for the unknown  x:\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2\" - \"2%283%2Fx%29%5E2\" = \"7\".\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by  \"x%5E2\".  You will get\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E4+-+7x%5E2+-+18\" = \"0\".\r
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\n" ); document.write( "\n" ); document.write( "Factor:\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B2%29%2A%28x%5E2-9%29\" = \"0\".\r
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\n" ); document.write( "\n" ); document.write( "The roots are  \"x%5E2\" = -\"2\"  and  \"x%5E2\" = \"9\".\r
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\n" ); document.write( "\n" ); document.write( "The real roots are  x = +/- 3.\r
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\n" ); document.write( "\n" ); document.write( "Correspondingly  y = +/- 1.\r
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\n" ); document.write( "\n" ); document.write( "Answer.  The pairs  (x,y) = (3,1)  and  (x,y) = (-3,-1)  are real solutions.\r
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