document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994108>Question 994108</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Rico can drive 2 times as fast as Luis can ride his bicycle. If it takes Luis 2 hours longer than Rico to travel 88 miles, how fast can Luis ride his bicycle? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613326 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613326\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R - time for Rico to drive 88 miles<BR>\n" );
document.write( "L - time for Luis to bike 88 miles<BR>\n" );
document.write( "R can drive 2 times faster, which means he will get to the end in 1/2 the time<BR>\n" );
document.write( "Now we have an equation:<BR>\n" );
document.write( "R=1/2L<BR>\n" );
document.write( "Also, it took Luis 2 hours longer than Rico:<BR>\n" );
document.write( "R+2=L<BR>\n" );
document.write( "Now, on this last equation let's substitute tha value of R:<BR>\n" );
document.write( "1/2L+2= L Subtract 1/2L from both sides<BR>\n" );
document.write( "2= 1/2L Now divido both sides by 1/2<BR>\n" );
document.write( "4= L, or L= 4 So it takes Luis 4 hours to do the 88 miles. Finally: <BR>\n" );
document.write( "v= d/t= 88/4= 22 miles per hour is Luis' speed  </SPAN>\n" );
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