document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994090>Question 994090</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length and the breadth of a rectengle are increased by 12% and x% respectively,thereby the area of the rectengle increased by 40%. What is the value of x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613291 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The length and the breadth of a rectengle are increased by 12% and x% respectively,thereby the area of the rectengle increased by 40%. What is the value of x?<BR>\n" );
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document.write( "Original DATA: length = L ; Breadth = B ; Area = LB?<BR>\n" );
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document.write( "New Area Equation:<BR>\n" );
document.write( "1.12L * (1+x/100)B = 0.40LB<BR>\n" );
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document.write( "1.12(1+x/100) = 0.4<BR>\n" );
document.write( "1+(x/100) = 1.25<BR>\n" );
document.write( "x/100 = 0.25<BR>\n" );
document.write( "x = 25<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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