document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994081>Question 994081</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Every now and then even a good diamond cutter has a problem and the diamond breaks. for one cutter, the rate of breaks is .1%.<BR>\n" );
document.write( "If this cutter works on 75 stones, what is the probability that he breaks 2 or more?\r<BR>\n" );
document.write( "\n" );
document.write( "I got 0.997420452. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613282 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> we use the binomial probability formula<BR>\n" );
document.write( "Probability(P) = (nCk) * p^k * q^(n-k) where nCk is the combination of n items taken k at a time<BR>\n" );
document.write( "********************************************************************<BR>\n" );
document.write( "P(k > or = 2) = 1 - ( P ( k = 0 ) + P ( k = 1 ) )<BR>\n" );
document.write( "p = .001, q = .999, n = 75<BR>\n" );
document.write( "P ( k = 0 ) = 0.927708673390002<BR>\n" );
document.write( "P ( k = 1 ) = 0.0696477983025527<BR>\n" );
document.write( "P(k > or = 2) = 1 - (0.927708673390002 + 0.0696477983025527)<BR>\n" );
document.write( "P(k > or = 2) = 0.002643528 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );