document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994064>Question 994064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A scientist needs 60 liters of a 60% acid solution. He currently has a 40% solution and a 70% solution. How many liters of each does he need to make the needed 60 liters of 60% acid solution?\r<BR>\n" );
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document.write( "Gabe neeeds ? liters of the 40% solution.\r<BR>\n" );
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document.write( "He also needs ? liters of the 70% solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613265 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A scientist needs 60 liters of a 60% acid solution. He currently has a 40% solution and a 70% solution. How many liters of each does he need to make the needed 60 liters of 60% acid solution? <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "acid + acid = acid<BR>\n" );
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document.write( "0.40x + 0.70(60-x) = 0.60*60<BR>\n" );
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document.write( "40x + 70*60 - 70x = 60*60<BR>\n" );
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document.write( "-30x = -10*60<BR>\n" );
document.write( "x = 20 liters<BR>\n" );
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document.write( "Gabe needs 20 liters of the 40% solution. <BR>\n" );
document.write( "He also needs 40 liters of the 70% solution. <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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