document.write( "Question 994052: Two painters, working together, can paint a house in 3 days.
\n" ); document.write( "One painter working alone can paint the house in 4 days.
\n" ); document.write( "How many days would it take the second painter, working alone,to paint the house.
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Algebra.Com's Answer #613257 by ikleyn(52786)\"\" \"About 
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\n" ); document.write( "Two painters, working together, can paint a house in 3 days.
\n" ); document.write( "One painter working alone can paint the house in 4 days.
\n" ); document.write( "How many days would it take the second painter, working alone,to paint the house.
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\n" ); document.write( "\n" ); document.write( "Let  \"x\"  be the number of days for the second painter to paint the house,  working alone.\r
\n" ); document.write( "\n" ); document.write( "Then the second painter paints  \"1%2Fx\"  of the house per day.  It is his rate of work.\r
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\n" ); document.write( "\n" ); document.write( "The first painter can paint  \"1%2F4\"  of the house per day.  It is his rate of work.\r
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\n" ); document.write( "\n" ); document.write( "Working together, they paint \"1%2F3\" of the house per day.\r
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\n" ); document.write( "\n" ); document.write( "It gives an equation\r
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\n" ); document.write( "\n" ); document.write( "\"1%2F4\" + \"1%2Fx\" = \"1%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "Simplify and solve it.  Multiply both sides by  12x  (it is the common denominator).  You will get\r
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\n" ); document.write( "\n" ); document.write( "3x + 12 = 4x.\r
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\n" ); document.write( "\n" ); document.write( "Hence, x = 12.\r
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\n" ); document.write( "\n" ); document.write( "Answer.  The second painter can paint the house in  15  days.\r
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\n" ); document.write( "\n" ); document.write( "For more problems on joint work see the lesson  Using fractions to solve word problems on joint work  in this site.\r
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