document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993738>Question 993738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A telemarketer earns $150 a week plus $2 for each call that results in a sale. Last week she earned a total of $204. How many of her calls resulted in sales? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613246 by </B><A HREF=/tutors/aboutme.mpl?userid=Alex2dadeath><B>Alex2dadeath(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alex2dadeath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Total is 204<BR>\n" );
document.write( "She guarantees a pay of 150. She gets $2 per call so it will be 2x (2 being the value and x being the calls)<BR>\n" );
document.write( "Set this into an equation: 2x+150=204\r<BR>\n" );
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document.write( "So now we subtract 150 from both sides to leave 2x alone<BR>\n" );
document.write( "2x+150 - 150 = 204 -150<BR>\n" );
document.write( "You are now left with: 2x=54<BR>\n" );
document.write( "Now she gets $2 per call. Divide 2 into both sides to get x alone. \r<BR>\n" );
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document.write( "54 divided by 2 equals 27. \r<BR>\n" );
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document.write( "ANSWER: X=27 CALLS </SPAN>\n" );
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