document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994045>Question 994045</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of a garden is 10 m more than twice the width. The are is 120m2. What are the dimensions of the garden to the nearest tenth metre? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613235 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> W=x<BR>\n" );
document.write( "L=2x+10<BR>\n" );
document.write( "area is 120 m^2<BR>\n" );
document.write( "Therefore, (2x+10)(x)=120<BR>\n" );
document.write( "2x^2+10x=120<BR>\n" );
document.write( "2x^2+10x-120=0<BR>\n" );
document.write( "divide by 2<BR>\n" );
document.write( "x^2+5x-60=0<BR>\n" );
document.write( "x=(1/2) { -5 +/- sqrt (25+240)}, and use positive root only<BR>\n" );
document.write( "sqrt 265=16.279<BR>\n" );
document.write( "x=(1/2)(-5+16.279)=(1/2)(11.279)=5.64 m<BR>\n" );
document.write( "2x+10=21.28<BR>\n" );
document.write( "convert to nearest tenth of a meter<BR>\n" );
document.write( "5.6*21.3=119.28<BR>\n" );
document.write( "rounded to two decimal places it is 120.02.<BR>\n" );
document.write( "The dimensions are 5.6 m x 21.3 m </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );