document.write( "Question 85100: hi, how would I be able to find an equation of the line through the point (-2/3, 1)with undefined slope? What process will I use? \n" ); document.write( "
Algebra.Com's Answer #61322 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! The undefined slope is the clue. It tells you that the graph is a vertical line. Why so? \n" ); document.write( "Because the slope will always have a real value as long as there is a change in x. Recall \n" ); document.write( "that the slope is defined as: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "But if the run (horizontal change or change in x) is zero, the slope is undefined \n" ); document.write( "because in algebra division by zero is not allowed. \n" ); document.write( ". \n" ); document.write( "Therefore, we know the horizontal change in the graph is zero. So the graph shows that no \n" ); document.write( "matter what the value of y is, x always has to be the same because it cannot change. \n" ); document.write( ". \n" ); document.write( "Now the question is where would the vertical line be. Well, since it has to go up through \n" ); document.write( "the y value of 1, it must have the x value that corresponds to the y value of 1. The problem \n" ); document.write( "tells you that the x corresponding x value is -2/3. \n" ); document.write( ". \n" ); document.write( "So the graph you are looking for is a vertical line that goes through -2/3 on the x axis \n" ); document.write( "and therefore, it goes through 1 in the y direction as well as lots of other y values in \n" ); document.write( "both the positive and negative direction. The equation for this line is x = -2/3. \n" ); document.write( "There is no y in the equation at all because y can be any value, but x always has to \n" ); document.write( "be -2/3 so that the line will go up through the value of y = 1. \n" ); document.write( ". \n" ); document.write( "Hope this helps you to understand the problem and its answer a little better. \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( " |