document.write( "Question 994014: A particle is moving around the ellipse 4x^2+16y^2 = 64. At any time t its x and y coordinates are given by x = 4cos(t) and y = 2sin(t). At what rate is the particle's distance to the origin changing when t = π/4?\r
\n" ); document.write( "\n" ); document.write( "I know this is a related rates problem. But I don't know how to set this problem up in order to solve. \r
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Algebra.Com's Answer #613214 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I would think this is a calculus problem.
\n" ); document.write( "The distance to the origin as a function of \"t\" (time) is
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\n" ); document.write( "The function showing the rate of change at time \"t\" is
\n" ); document.write( "\"dD%2Fdt\" , and it can be calculated using the chain rule
\n" ); document.write( "\"D%28t%29=2%2AF%28G%28t%29%29\" with \"F%28u%29=sqrt%28u%29=u%5E%28%221%2F2%22%29\" and \"u=G%28t%29=4%28cos%28t%29%29%5E2%2B%28sin%28t%29%29%5E2\"
\n" ); document.write( "\"dF%2Fdu=%281%2F2%29u%5E%28%22-1%2F2%22%29=1%2F%282u%5E%28%221%2F2%22%29%29=1%2F2sqrt%28u%29\" , and
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\n" ); document.write( "Applying the chain rule again, and again, to both terms:
\n" ); document.write( " and
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\n" ); document.write( "So, , and
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\n" ); document.write( "Substituting the expression for \"u\" ,
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\n" ); document.write( "For \"t=pi%2F4\" ,
\n" ); document.write( "\"t=pi%2F4\"-->-->-->
\n" ); document.write( "-->\"rate%28pi%2F4%29=%28-6%282%2F4%29%29%2Fsqrt%284%282%2F4%29%2B%282%2F4%29%29%29%29\"-->\"rate%28pi%2F4%29=-3%2Fsqrt%285%2F2%29\"-->\"rate%28pi%2F4%29=-3sqrt%282%29%2Fsqrt%285%29\"-->\"rate%28pi%2F4%29=-3sqrt%2810%29%2F5\"
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