document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=994005>Question 994005</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me i'm weak in speed/distance chapter\r<BR>\n" );
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document.write( "Ques1.<BR>\n" );
document.write( "Two drivers, Mike and Peter, travel from Town A to Town B, 112 km away.<BR>\n" );
document.write( "They start at the same time and take the same route.<BR>\n" );
document.write( "They travel at the average speed of 56 km/h and 64 km/h respectively.<BR>\n" );
document.write( "When Peter reaches Town B, how far behind is Mike?\r<BR>\n" );
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document.write( "Quest2.\r<BR>\n" );
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document.write( "The distance between two town X and Y is 28 km. A car and a lorry leave X at 08.00 to travel to Y. On arriving at Y, the car then returns to X on the same route. When the two vehicles meet, the distance they have travelled are in the ratio 3:5. The average speed of the lorry is 42 km/h.\r<BR>\n" );
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document.write( "Calculate\r<BR>\n" );
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document.write( "(a) the time at which the two vehicles meet.<BR>\n" );
document.write( "(b) the average speed of the car in km/h </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613201 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613201\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The time that Peter needs to travel from A to B is 112 km/64 km/h=7/4 h.<BR>\n" );
document.write( "The time that Mike needs to travel from A to B is 112 km/56 km/h=2h<BR>\n" );
document.write( "Peter reaches at B 2-7/4=1/4 h before Mike.<BR>\n" );
document.write( "Since Mike travel at the average speed of 56 km/h he will be behind Peter 56km/h*1/4 h= 14 km. </SPAN>\n" );
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