document.write( "Question 85102: I have a question that states: find the graph of f(x)=3(x-4)^2+2. How do I do this problem? I have tried and can't get it. \n" ); document.write( "
Algebra.Com's Answer #61318 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
find the graph of f(x)=3(x-4)^2+2.
\n" ); document.write( "Rewrite in the form:
\n" ); document.write( "y-2 = 3(x-4)^2
\n" ); document.write( "This is the vertex form of a parabola.
\n" ); document.write( "The vertex is at (4,2)
\n" ); document.write( "Since 3>0 the parabola opens up.
\n" ); document.write( "If x=0, y=3(-4)^2+2 = 50 giving (0,50) as the y-intercept
\n" ); document.write( "Plot the vertex and the intercept and draw the parabola.
\n" ); document.write( "\"graph%28400%2C300%2C-10%2C20%2C-5%2C60%2C3%28x-4%29%5E2%2B2%29\"
\n" ); document.write( "==========
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );