document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993978>Question 993978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man invest a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613171 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A man invests a certain amount of money at 2% interest and $800 more than that amount in another account at 4% interest. At the end of one year, he earned $92 in interest. How much money was invested in each account<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "int + int = 92 dollars<BR>\n" );
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document.write( "0.02x + 0.04(x+800) = 92<BR>\n" );
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document.write( "2x + 4x + 3200 = 9200<BR>\n" );
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document.write( "6x = 6000<BR>\n" );
document.write( "x = 1000 (amt. invested at 2%)<BR>\n" );
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document.write( "x+800 = 1800 (amt. invested at 4%)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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