document.write( "Question 993856: x+2y+0z+3w=0
\n" ); document.write( "0x+y+z+w=1
\n" ); document.write( "0x+y+0z+w=2
\n" ); document.write( "x+2y+0z+2w=3 \n" ); document.write( "

Algebra.Com's Answer #613123 by Alan3354(69443) $\"\"$ $\"About$

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x+2y+0z+3w=0
\n" ); document.write( "0x+y+z+w=1
\n" ); document.write( "0x+y+0z+w=2
\n" ); document.write( "x+2y+0z+2w=3
\n" ); document.write( "----------
\n" ); document.write( "0x+y+z +w =1 Eqn 2
\n" ); document.write( "0x+y+0z+w=2 Eqn 3
\n" ); document.write( "===================================== Subtract
\n" ); document.write( "z = -1 ******************
\n" ); document.write( "-----
\n" ); document.write( "x+2y+3w= 0
\n" ); document.write( "0x+y+ w= 2 times 2 --> 0x+2y+2w = 4 Eqn A
\n" ); document.write( "x +2y+2w = 3
\n" ); document.write( "0x+2y+2w = 4 Eqn A
\n" ); document.write( "===================================== Subtract
\n" ); document.write( "x = -1 **********************
\n" ); document.write( "-----
\n" ); document.write( "0x+y+0z+w=2 Eqn 3
\n" ); document.write( "x+2y+0z+2w=3 Eqn 4
\n" ); document.write( "-----
\n" ); document.write( "y + w = 2 Eqn 3
\n" ); document.write( "2y + 2w = 4 Eqn 4 times 2 --> y + w = 2, same as Eqn 3
\n" ); document.write( "=======================
\n" ); document.write( "--> dependent system, no unique solution.
\n" ); document.write( " \n" ); document.write( "

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