document.write( "Question 993952: A total of $700 is invested for one year. Some of it is invested at 4% and the rest of it is
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document.write( "invested at 5%. At the end of the year, the total amount of interest earned is $30.
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document.write( "An amount of was invested at 4% and was invested at 5% \n" );
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Algebra.Com's Answer #613118 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x is invested at 4% \n" ); document.write( "700-x is invested at 5% \n" ); document.write( "0.04x+(700-x)(0.05)=0.04x + 35-0.05x=30 \n" ); document.write( "-0.01x=-5 \n" ); document.write( "x=500 \n" ); document.write( "700-x=200 \n" ); document.write( "$500 @ 4%=$20 \n" ); document.write( "200 @ 5%=$10 \n" ); document.write( "$30 total, check. \n" ); document.write( " |