document.write( "Question 993904: Two cyclists, 45 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 3 hours later, what is the speed (in mi/h) of the faster cyclist? \n" ); document.write( "

Algebra.Com's Answer #613112 by fractalier(6550) $\"\"$ $\"About$

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The easy way: They cover 45 miles in 3 hours. Their combined speed must be 15 miles an hour. Thus the slower guy travels at 5 mph and the faster at 10 mph.\r
\n" ); document.write( "\n" ); document.write( "The harder way: If we call the rate of the slower rider R, the faster rider travels at 2R. Since they travel the same 3 hours, one guy travels 3R miles and the other travels 6R miles. Added together, they cover 45 miles, or\r
\n" ); document.write( "\n" ); document.write( "3R + 6R = 45
\n" ); document.write( "9R = 45
\n" ); document.write( "R = 5
\n" ); document.write( "2R = 10 miles per hour \n" ); document.write( "

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