document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993929>Question 993929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The gas tank on your car holds 21 gallons. If you get between 16 and 18 miles <BR>\n" );
document.write( "per gallon depending on conditions, write an inequality stating how far you can on a tank of gas.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613093 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613093\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the number of miles you can go on a tank of gas.\r<BR>\n" );
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document.write( "if you get 16 miles per gallon, then x = 21 * 16.\r<BR>\n" );
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document.write( "if you get 18 miles per gallon, than x = 21 * 18.\r<BR>\n" );
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document.write( "x has to be greater than or equal to 21 * 16.\r<BR>\n" );
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document.write( "x has to be less than or equal to 21 * 18.\r<BR>\n" );
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document.write( "if x is greater than or equal to 16 * 21, then 16 * 21 must be less  than or equal to x.\r<BR>\n" );
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document.write( "you can now write your inequality as 16 * 21 is less than or equal to x which is less than or equal to 18 * 21.\r<BR>\n" );
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document.write( "the symbol for less than or equal to is <=.\r<BR>\n" );
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document.write( "your inequality can therefore be expressed as 16 * 21 <= x <= 21 * 18.\r<BR>\n" );
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document.write( "simplify this further to get:\r<BR>\n" );
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document.write( "336 <= x <= 378\r<BR>\n" );
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document.write( "this says that the minimum number of miles you will travel on a tank of gas is 336 miles and the maximum number of miles you will travel on the same tank of gas is 378.\r<BR>\n" );
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