document.write( "Question 993911: Hi, please help me find x in this equation: \"2%2B5%2F%28x-4%29+=+%28x%2B1%29%2F%28x-4%29\" \n" ); document.write( "
Algebra.Com's Answer #613082 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\"2%2B5%2F%28x-4%29\" = \"%28x%2B1%29%2F%28x-4%29\".\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by (x-4).\r
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\n" ); document.write( "\n" ); document.write( "You will get\r
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\n" ); document.write( "\n" ); document.write( "2*(x-4) + 5 = x+1.\r
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\n" ); document.write( "\n" ); document.write( "Simplify:\r
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\n" ); document.write( "\n" ); document.write( "2x - 8 + 5 = x + 1.\r
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\n" ); document.write( "\n" ); document.write( "x = 4.\r
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\n" ); document.write( "\n" ); document.write( "But  x = 4  is prohibited,  because the original equation has  (x-4)  in the denominators.  It is prohibited to divide by zero.\r
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\n" ); document.write( "\n" ); document.write( "Thus the equation has no solutions.\r
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\n" ); document.write( "\n" ); document.write( "The plot of \"2%2B5%2F%28x-4%29+-+%28x%2B1%29%2F%28x-4%29\"\r
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