document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993905>Question 993905</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the linear system using substitution.\r<BR>\n" );
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document.write( "4x - y = 5<BR>\n" );
document.write( "4x + 4 = -4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613078 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52787)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613078\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=system%284x+-+y+=+5%2C%0D%0A4x+%2B+4+=+-4%29 ALIGN=MIDDLE  ALT=\"system%284x+-+y+=+5%2C%0D%0A4x+%2B+4+=+-4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "From the second equation you have &nbsp;4x = -8, &nbsp;hence, &nbsp;x = -2.\r<BR>\n" );
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document.write( "Substitute it into the first equation and solve for &nbsp;y.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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