document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=84892>Question 84892</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For the linear equation in standard form 2x+5y=6:<BR>\n" );
document.write( "a) Find the slope of this line<BR>\n" );
document.write( "b) Find the slope of a line parallel to this line<BR>\n" );
document.write( "c) Find the slope of a line perpendicular to this line<BR>\n" );
document.write( "d) use your answers to part c) to write the equation of the line which is perpendicular to the given line and passes through the point (-3,-4). Put final equation in standard form. Thanks:)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61302 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the linear equation in standard form 2x + 5y = 6:<BR>\n" );
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document.write( "a) Find the slope of this line:<BR>\n" );
document.write( "Find the slope by putting the equation into the slope/intercept form y = mx + b<BR>\n" );
document.write( "2x + 5y = 6:<BR>\n" );
document.write( "5y = -2x + 6; subtracted 2x from both sides<BR>\n" );
document.write( "y = -(2/5)x + (6/5)<BR>\n" );
document.write( "Slope (m) = -2/5<BR>\n" );
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document.write( "b) Find the slope of a line parallel to this line<BR>\n" );
document.write( "Parallel lines have equal slopes, therefore its slope = -2/5 also<BR>\n" );
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document.write( "c) Find the slope of a line perpendicular to this line<BR>\n" );
document.write( "The relationship of slopes of perpendicular lines: m1*m2 = -1<BR>\n" );
document.write( "-2/5 * m2 = -1<BR>\n" );
document.write( "m2 = -1 * -5/2<BR>\n" );
document.write( "m2 = +5/2 is the slope of a perpendicular line<BR>\n" );
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document.write( "d) use your answers to part c) to write the equation of the line which is perpendicular to the given line and passes through the point (-3,-4).<BR>\n" );
document.write( "Use the point/slope form y - y1 = m(x - x1)<BR>\n" );
document.write( "x1 = -3; y1 = -4; m = 5/2<BR>\n" );
document.write( "y - (-4) = 5/2(x - (-3))<BR>\n" );
document.write( "y + 4 = 5/2 (x + 3)<BR>\n" );
document.write( "y + 4 = (5/2)x + 15/2<BR>\n" );
document.write( "y = (5/2)x + 15/2 - 4<BR>\n" );
document.write( "Y = (5/2)x + 15/2 - 8/2<BR>\n" );
document.write( "y = (5/2)x + 7/2<BR>\n" );
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document.write( "Put final equation in standard form:<BR>\n" );
document.write( "Multiply equation  by 2 to get rid of the denominators<BR>\n" );
document.write( "2y = 5x + 7; subtract 5x from both sides<BR>\n" );
document.write( "-5x + 2y = 7;  the standard form </SPAN>\n" );
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