document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993832>Question 993832</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A part of $8000 was borrowed at 2% simple annual interest and the remainder at 4%. If the total amount of interest<BR>\n" );
document.write( "after a year is $280, how much each was borrowed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #613011 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=613011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's call the part borrowed at 2% a and the remainder b:<BR>\n" );
document.write( "a+b= 8,000, therefore, a= 8,000-b We will use this value for a.<BR>\n" );
document.write( "And the problem says that after a year the interest amounts to 280:<BR>\n" );
document.write( "0.02(8000-b)+0.04b = 280 Now multiply on the left:<BR>\n" );
document.write( "160-0.02b+0.04b= 280 Add the b on left and subtract 160 from both sides:<BR>\n" );
document.write( "0.02b= 120 divide both sides by 0.02:<BR>\n" );
document.write( "b= 6,000. This amount was borrowed at 4%, so 8,000-6,000= 2,000 was borrowed at 2%. Let's prove it:<BR>\n" );
document.write( "6,000*0.04= 240<BR>\n" );
document.write( "2,000*0.02=  40<BR>\n" );
document.write( "Total.......280 We have the correct answer. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );