document.write( "Question 1799: solve the system
\n" ); document.write( "x+y+z=6
\n" ); document.write( "3x+4y-7z=1
\n" ); document.write( "2x-y+3z=5
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #613 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
these are just simultaneous equations...3 unknowns and 3 equations...solvable, if tedious.\r
\n" ); document.write( "\n" ); document.write( "You need to start with 2 equations and get rid of 1 variable...looking at the 3 equations, use 1 and 3, as they both have a y, so easy to remove these...\r
\n" ); document.write( "\n" ); document.write( "1 is \"+x+%2B+y+%2B++z+=+6\"
\n" ); document.write( "3 is \"2x+-+y+%2B+3z+=+5\"\r
\n" ); document.write( "\n" ); document.write( "the y's have Different signs so aDD (note the DD). Similarly, Same signs, then Subtract!!\r
\n" ); document.write( "\n" ); document.write( "so, we get equation 4\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+4z+=+11\"\r
\n" ); document.write( "\n" ); document.write( "Now repeat the process with 2 other equations, say 2 and 3\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+4y+-+7z+=+1\"
\n" ); document.write( "\"2x+-++y+%2B+3z+=+5\"\r
\n" ); document.write( "\n" ); document.write( "Again I will choose to get rid of the y term, but i need to increase the lower equation by a factor of 4, to get the 2 equations to match....\r
\n" ); document.write( "\n" ); document.write( "\"3x+%2B+4y+-++7z+=++1\"
\n" ); document.write( "\"8x+-+4y+%2B+12z+=+20\"\r
\n" ); document.write( "\n" ); document.write( "The y-terms have Different signs therefore we aDD, getting equation 5...\r
\n" ); document.write( "\n" ); document.write( "\"11x+%2B+5z+=+21\"\r
\n" ); document.write( "\n" ); document.write( "Now we use 4 and 5 to get rid of another variable...i choose to remove the z's, by making them both 20z...\r
\n" ); document.write( "\n" ); document.write( "equation 4 needs to be multiplied by 5: \"+3x+%2B+4z+=+11\"
\n" ); document.write( "equation 5 needs to be multiplied by 4: \"11x+%2B+5z+=+21\" \r
\n" ); document.write( "\n" ); document.write( "This gives us\r
\n" ); document.write( "\n" ); document.write( "\"15x+%2B+20z+=+55\"
\n" ); document.write( "\"44x+%2B+20z+=+84\"\r
\n" ); document.write( "\n" ); document.write( "Here the z terms have the Same sign therefore we Subtract the 2 equations, giving us \"%28-29x%29=%28-29%29\", so x=1.\r
\n" ); document.write( "\n" ); document.write( "We now substitute this into 4 or 5, to find z (z=2) and then these into equation 1, 2 or 3 to find y (y=3).\r
\n" ); document.write( "\n" ); document.write( "THEN you double check each of the original equations (1, 2 and 3) to make sure that your answers are correct.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( "Jon.
\n" ); document.write( "
\n" );