document.write( "Question 993758: The sum of 2 numbers is 110. The larger number is 2 less than 7 times the smaller. Find the larger number
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Algebra.Com's Answer #612976 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let numbers be \"x\" and \"y\", and let \"x\" be larger number\r
\n" ); document.write( "\n" ); document.write( "if the sum of \"2\" numbers is \"110\", we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2By=110\"\r
\n" ); document.write( "\n" ); document.write( "\"y=110-x\".........eq.1\r
\n" ); document.write( "\n" ); document.write( "if the larger number \"x\" is \"2\" less than \"7\" times the smaller number \"y\" we have\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2=7y\"\r
\n" ); document.write( "\n" ); document.write( "\"y=%28x%2B2%29%2F7\"......eq.2\r
\n" ); document.write( "\n" ); document.write( "to find the larger number \"x\" equal the right sides of eq.1 and eq.2:\r
\n" ); document.write( "\n" ); document.write( "\"110-x=%28x%2B2%29%2F7\".........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"7%28110-x%29=%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"770-7x=x%2B2\"\r
\n" ); document.write( "\n" ); document.write( "\"770-2=x%2B7x\"\r
\n" ); document.write( "\n" ); document.write( "\"768=8x\"\r
\n" ); document.write( "\n" ); document.write( "\"768%2F8=x\"\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28x=96%29\"=> larger number\r
\n" ); document.write( "\n" ); document.write( "and smaller number is:\r
\n" ); document.write( "\n" ); document.write( "\"y=110-96\"\r
\n" ); document.write( "\n" ); document.write( "\"y=14\"\r
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