document.write( "Question 993705: three consecutive numbers are to be found such that three times the smallest plus five times the middle number minus four times the largest is 37. find the numbers \n" ); document.write( "

Algebra.Com's Answer #612938 by Cromlix(4381) $\"\"$ $\"About$

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Hi there,
\n" ); document.write( "3 consecutive numbers:-
\n" ); document.write( "n, n + 1, n + 2.
\n" ); document.write( "3(n) + 5(n + 1) - 4(n + 2) = 37
\n" ); document.write( "3n + 5n + 5 - 4n - 8 = 37
\n" ); document.write( "Collect like terms.
\n" ); document.write( "3n + 5n - 4n = 37 - 5 + 8
\n" ); document.write( "4n = 40
\n" ); document.write( "n = 10.
\n" ); document.write( "3 consecutive numbers:-
\n" ); document.write( "10,11,12.
\n" ); document.write( "Hope this helps :-) \n" ); document.write( "

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