document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993705>Question 993705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three consecutive numbers are to be found such that three times the smallest plus five times the middle number minus four times the largest is 37. find the numbers  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612937 by </B><A HREF=/tutors/aboutme.mpl?userid=LinnW><B>LinnW(1048)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LinnW><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=LinnW><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612937\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the first number.<BR>\n" );
document.write( "x + 1 is the second<BR>\n" );
document.write( "x + 2 is the third<BR>\n" );
document.write( "3( the smallest ) + 5( the middle )  -4( the largest ) = 37<BR>\n" );
document.write( "3(x) + 5(x+1) -4(x+2) = 37<BR>\n" );
document.write( "3x + 5x + 5 -4x -8 = 37<BR>\n" );
document.write( "reorder<BR>\n" );
document.write( "3x + 5x -4x + 5 -8 = 37<BR>\n" );
document.write( "4x - 3 = 37<BR>\n" );
document.write( "add 3 to each side<BR>\n" );
document.write( "4x - 3 + 3 = 37 + 3<BR>\n" );
document.write( "4x = 40<BR>\n" );
document.write( "divide each side by 4<BR>\n" );
document.write( " x = 10<BR>\n" );
document.write( "So the numbers are 10,11,12<BR>\n" );
document.write( "Contact me if you would like additional assistance.<BR>\n" );
document.write( "I can work with you using an online whiteboard. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );