document.write( "Question 993688: If an object is projected vertically upward from ground level with an initial velocity of 240 ft/sec, then its distance s above the ground after t seconds is given by s = −12t^2 + 240t.For what values of t will the object be more than 1188 feet above the ground? \n" ); document.write( "
Algebra.Com's Answer #612900 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 1188>-12t^2+240t \n" ); document.write( "-12t^2+240t-1188<0 \n" ); document.write( "-t^2+20t-99<0 \n" ); document.write( "t^2-20t+99>0 \n" ); document.write( "(t-11)(t-9).0 \n" ); document.write( "at t>9 and <11 seconds. \n" ); document.write( "at 9 seconds, -972+2160=1188 \n" ); document.write( "at 11 seconds, -1452+2640=1188\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |