document.write( "Question 993688: If an object is projected vertically upward from ground level with an initial velocity of 240 ft/sec, then its distance s above the ground after t seconds is given by s = −12t^2 + 240t.For what values of t will the object be more than 1188 feet above the ground? \n" ); document.write( "
Algebra.Com's Answer #612900 by Boreal(15235)\"\" \"About 
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1188>-12t^2+240t
\n" ); document.write( "-12t^2+240t-1188<0
\n" ); document.write( "-t^2+20t-99<0
\n" ); document.write( "t^2-20t+99>0
\n" ); document.write( "(t-11)(t-9).0
\n" ); document.write( "at t>9 and <11 seconds.
\n" ); document.write( "at 9 seconds, -972+2160=1188
\n" ); document.write( "at 11 seconds, -1452+2640=1188\r
\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C200%2C-10%2C15%2C-50%2C1500%2C-12x%5E2%2B240x%29\"\r
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