document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=12058>Question 12058</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dorie, 42 years old has a 12 year old nephew, in how many years will the aunt be twice as old as her nephew?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6129 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dorie, 42 years old has a 12 year old nephew, in how many years will the aunt be twice as old as her nephew?\r<BR>\n" );
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document.write( "You would use the same equation as #12057\r<BR>\n" );
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document.write( "42+x=2(12+x)<BR>\n" );
document.write( "42+x=24+2x<BR>\n" );
document.write( "Subtract x from both sides and 24 from both sides.<BR>\n" );
document.write( "42-24=2x-x<BR>\n" );
document.write( "18=x<BR>\n" );
document.write( "check:\r<BR>\n" );
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document.write( "42+18=2(12+18)<BR>\n" );
document.write( "60=2(30)<BR>\n" );
document.write( "60=60\r<BR>\n" );
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document.write( "Hope this helps =)\r<BR>\n" );
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