document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993677>Question 993677</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One solution contains 40% alcohol and another contains 72% alcohol. How much of each should be mixed together to obtain 16 ounces of a 62% alcohol solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612894 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the amount of 40% alcohol.  The 16-x must be the amount of 72% alcohol.  The equation becomes, once you make percents into whole numbers...\r<BR>\n" );
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document.write( "x(40) + (16-x)(72) = 16(62)<BR>\n" );
document.write( "40x + 1152 - 72x = 992<BR>\n" );
document.write( "Simplifying gives<BR>\n" );
document.write( "-32x = -160<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x = 5<BR>\n" );
document.write( "So 5 oz of 40% and 11 oz of 72% will do the trick. </SPAN>\n" );
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