document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993651>Question 993651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a film, a character is criticized for marrying a woman when he is three times her age. He witty replies \"ah but in 24 years time I will only be twice her age\". How old are they </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612866 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( " he is three times her age. <BR>\n" );
document.write( "M = 3W<BR>\n" );
document.write( "ah but in 24 years time I will only be twice her age\". <BR>\n" );
document.write( "M + 24 = 2(W + 24)<BR>\n" );
document.write( "Replace M with 3W from top equation.<BR>\n" );
document.write( "3W + 24 = 2W + 48<BR>\n" );
document.write( "Collect like terms.<BR>\n" );
document.write( "3W - 2W = 48 - 24<BR>\n" );
document.write( "W = 24<BR>\n" );
document.write( "Woman is 24 years old.<BR>\n" );
document.write( "Man is 72 years old.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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