document.write( "Question 993634: determined the quadratic function whose graph is given. the vertex is (3,-11) and the y-intercept is -2 \n" ); document.write( "
Algebra.Com's Answer #612864 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "given:the vertex is (\"3\",\"-11\") and the y-intercept is \"-2\"\r
\n" ); document.write( "\n" ); document.write( "use vertex form of equation:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+a%28x+-+h%29%5E2+%2B+k\" where vertex: (\"h\",\"k\") and y-intercept: (\"x\",\"y\")\r
\n" ); document.write( "\n" ); document.write( "so, we will use given points to find coefficient \"a\":\r
\n" ); document.write( "\n" ); document.write( "vertex: (\"h\",\"k\")= (\"3\",\"-11\") and
\n" ); document.write( "the y-intercept (\"x\",\"y\")= (\"0\",\"-2\")\r
\n" ); document.write( "\n" ); document.write( "\"-2+=+a%280+-+3%29%5E2+-11\" \r
\n" ); document.write( "\n" ); document.write( "\"-2+=+a%28+-+3%29%5E2+-11\"\r
\n" ); document.write( "\n" ); document.write( "\"-2%2B11+=+9a+\" \r
\n" ); document.write( "\n" ); document.write( "\"9+=+9a+\" \r
\n" ); document.write( "\n" ); document.write( "\"a=1\"\r
\n" ); document.write( "\n" ); document.write( "so your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%28x+-+3%29%5E2+-11\"\r
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