document.write( "Question 993613: Chris is driving across the country. She drives for 5 1/2 hours each day. the first day, she drove a total of 264 miles. driving at this same rate, how far can chris drive each week on the average? \n" ); document.write( "
Algebra.Com's Answer #612828 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "if she drives for \"5\"\"+1%2F2\" hours each day, and the first day, she drove a total of \"264\" miles, we have\r
\n" ); document.write( "\n" ); document.write( "\"t=5\"\"+1%2F2\" hours which is \"t=5.5h\" and \"d=264mil\"\r
\n" ); document.write( "\n" ); document.write( "so, we can find average speed \"s\":\r
\n" ); document.write( "\n" ); document.write( "\"s=d%2Ft\"\r
\n" ); document.write( "\n" ); document.write( "\"s=264mil%2F5.5h\"\r
\n" ); document.write( "\n" ); document.write( "\"s=2640mil%2F55h\"\r
\n" ); document.write( "\n" ); document.write( "\"s=48%28mil%2Fh%29\"\r
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\n" ); document.write( "driving at this same rate each week (which is \"7\" days) she will on the average she can drive as far as:\r
\n" ); document.write( "\n" ); document.write( "\"d=s%287t%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d=48%28mil%2Fh%29%287%2A5.5h%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d=48%28mil%2Fcross%28h%29%29%2838.5cross%28h%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d=48mil%2A38.5\"\r
\n" ); document.write( "\n" ); document.write( "\"d=1848mil\"\r
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