document.write( "Question 993576: The length of a rectangle is 17 meters less than twice the width. The perimeter of the rectangle is 203 meters. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #612825 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Make the width = 'x' \n" ); document.write( "Length = 2x - 17 \n" ); document.write( "Perimeter = 2 x Width + 2 x Length \n" ); document.write( "203 = 2(x) + 2(2x - 17) \n" ); document.write( "203 = 2x + 4x - 34 \n" ); document.write( "collect like terms. \n" ); document.write( "2x + 4x = 203 + 34 \n" ); document.write( "6x = 237 \n" ); document.write( "x = 237/6 \n" ); document.write( "x = 39.5 meters \n" ); document.write( "Width = 39.5 meters \n" ); document.write( "Length = 62 meters \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |