document.write( "Question 993576: The length of a rectangle is 17 meters less than twice the width. The perimeter of the rectangle is 203 meters. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #612825 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Make the width = 'x'
\n" ); document.write( "Length = 2x - 17
\n" ); document.write( "Perimeter = 2 x Width + 2 x Length
\n" ); document.write( "203 = 2(x) + 2(2x - 17)
\n" ); document.write( "203 = 2x + 4x - 34
\n" ); document.write( "collect like terms.
\n" ); document.write( "2x + 4x = 203 + 34
\n" ); document.write( "6x = 237
\n" ); document.write( "x = 237/6
\n" ); document.write( "x = 39.5 meters
\n" ); document.write( "Width = 39.5 meters
\n" ); document.write( "Length = 62 meters
\n" ); document.write( "Hope this helps :-)
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