document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993564>Question 993564</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Danny and Mary want to go to a concert next weekend. the tickets will cost $70. After Mary gives Danny all the money she has in her wallet. Danny must come up with $5 less than twice Mary's contribution to pay for the tickets. How much will each contribute for the tickets? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612798 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612798\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mary gave her money to Danny. We'll call her money x<BR>\n" );
document.write( "Danny must come up with $5 less than 2x, this is, 2x-5. Finally:<BR>\n" );
document.write( "x+2x-5= 70 add 5 on both sides<BR>\n" );
document.write( "x+2x= 75 Add x on left<BR>\n" );
document.write( "3x= 75 Divide both sides by 3<BR>\n" );
document.write( "x= 25 This is how much money Mary gave Danny. So, Danny must come up with:<BR>\n" );
document.write( "25*2-5= 50-5= 45 This is the amount Danny must come up with. Let's see if it's true:<BR>\n" );
document.write( "25 Mary + 45 Danny = 25+45= 70 We've got the right answer. </SPAN>\n" );
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