document.write( "Question 993532: How do you solve 4x+5y=25 and 8x-5y=35 when using substitution
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Algebra.Com's Answer #612792 by ikleyn(52797)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "How do you solve 4x+5y=25 and 8x-5y=35 when using substitution. \n" ); document.write( "----------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You can express 4x from the first equation, 4x = 25-5y, and then substitute it into the second equation. You will get\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2*(25-5y) - 5y = 35.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Simplify and solve:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50 - 10y - 5y = 35,\r \n" ); document.write( "\n" ); document.write( "15y = 30 - 35,\r \n" ); document.write( "\n" ); document.write( "15y = 15, \r \n" ); document.write( "\n" ); document.write( "y = 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now substitute the found value of y=1 into the first equation to find x. You will get \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4x + 5*1 = 25,\r \n" ); document.write( "\n" ); document.write( "4x = 20, \r \n" ); document.write( "\n" ); document.write( "x = 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer. x = 5, y = 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |