document.write( "Question 85028: Please help me solve this equation:
\n" ); document.write( "the quantity of x plus the square root of y..cubed
\n" ); document.write( "i'm not sure how to write it on the computer--
\n" ); document.write( "(x + square root y)^3
\n" ); document.write( "i know that i should separate it all out, but how do you foil a cubed equation?
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Algebra.Com's Answer #61277 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Given:
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\n" ); document.write( "\"%28x+%2B+sqrt%28y%29%29%5E3\"
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\n" ); document.write( "Two lessons in here. This will probably be better to work with if you replace the square
\n" ); document.write( "root sign with its equivalent exponent. Remember that raising something to the (1/2) power
\n" ); document.write( "is the same as taking the square root of it. So let's replace the square root of y with the
\n" ); document.write( "quantity \"y%5E%281%2F2%29\". This makes the problem become:
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\n" ); document.write( "\"x+%2B+y%5E%281%2F2%29\"
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\n" ); document.write( "Next let's think about what is going on when you use the FOIL method. The term FOIL is
\n" ); document.write( "just a memory jogger to help you remember what you can do to multiply two quantities
\n" ); document.write( "that have two terms in each quantity. Let's take a little time to think about what you
\n" ); document.write( "are doing when you \"FOIL\". Suppose you have the two terms:
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\n" ); document.write( "(a + b)*(c + d)
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\n" ); document.write( "If you FOIL them you get (a*c)+(a*d)+(b*c)+(b*d). Now I'm going to ask you to look at
\n" ); document.write( "what you did. You took the first term in the first set of parentheses and you used it
\n" ); document.write( "to multiply both terms in the second set. Then you took the second term in the first set
\n" ); document.write( "of parentheses and you used it to multiply both terms in the second set. No magic there,
\n" ); document.write( "but you lose sight of what you are doing by saying Firsts, Outsides, Insides, Lasts.
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\n" ); document.write( "Now I'm going to propose something very similar to FOIL, but one set of parentheses
\n" ); document.write( "will contain three terms. Suppose you have:
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\n" ); document.write( "(a + b)*(c + d + e)
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\n" ); document.write( "How do you do that? FOIL doesn't apply does it? Well, you just use a process similar to
\n" ); document.write( "the one I suggested in the first case. Take the first term in the first set of parentheses
\n" ); document.write( "(that is the term \"a\") and you multiply it by all three terms in the second set so that you
\n" ); document.write( "get ac + ad + ae. Then you take the second term in the first set (that term is \"b\") and
\n" ); document.write( "you multiply it by all three terms in the second set and you get bc + bd + be. Then you
\n" ); document.write( "combine the two sets of answers to get ac + ad + ae + bc + bd + be. And you can use the
\n" ); document.write( "same process for other problems. Take the terms one at a time from the first set of parentheses
\n" ); document.write( "and multiply them by each of the terms in the second set. When you are finished with all
\n" ); document.write( "the terms from the first set of parentheses, add all the answers together to get the whole
\n" ); document.write( "product.
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\n" ); document.write( "To me, it's easier to remember that method that FOIL, and it works for all sorts of products ...
\n" ); document.write( "even ones such as (a + b + c + d)*(e + f + g + h + i)
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\n" ); document.write( "For this example you would take a and multiply it by all 5 terms in the second set, then
\n" ); document.write( "take b and multiply it by all 5, then take c and do the same, then take d and also do
\n" ); document.write( "the same. When you get through with all those just add them up and you have the answer.
\n" ); document.write( "Try doing that with FOIL ...
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\n" ); document.write( "OK. Back to your problem. We said that we would substitute \"y%5E%281%2F2%29\" for the square root
\n" ); document.write( "of y and the problem would, therefore, become:
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\n" ); document.write( "\"%28x+%2B+y%5E%281%2F2%29%29%5E3\"
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\n" ); document.write( "I think you were on the right track thinking that you could split this into:
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\n" ); document.write( "\"%28x+%2B+y%5E%281%2F2%29%29%2A%28x+%2B+y%5E%281%2F2%29%29%2A%28x+%2B+y%5E%281%2F2%29%29\"
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\n" ); document.write( "which would be the same as cubing it. Then you would take the first two terms and FOIL
\n" ); document.write( "them to get the square of \"%28x%2By%5E%281%2F2%29%29\" and then multiply that by \"%28x+%2B+y%5E%281%2F2%29%29\"
\n" ); document.write( "to get the answer.
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\n" ); document.write( "So let's multiply the first two terms:
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\n" ); document.write( "\"%28x+%2B+y%5E%281%2F2%29%29%2A%28x+%2B+y%5E%281%2F2%29%29\"
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\n" ); document.write( "Multiplying the x times all the terms in the second set of parentheses and then doing the same
\n" ); document.write( "for multiplying the \"y%5E%281%2F2%29\" times the terms in the second set results in:
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\n" ); document.write( "\"x%5E2+%2B+xy%5E%281%2F2%29+%2B+xy%5E%281%2F2%29+%2B+y\"
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\n" ); document.write( "Note that \"y%5E%281%2F2%29%2Ay%5E%281%2F2%29+=+y%5E%281%2F2%2B1%2F2%29+=+y+%5E1+=+y\". And you can combine the two
\n" ); document.write( "terms in the middle. As a result the product of the first two terms is:
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\n" ); document.write( "\"x%5E2+%2B2xy%5E%281%2F2%29+%2B+y+\"
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\n" ); document.write( "Now you need to multiply that again by \"%28x+%2B+y%5E%281%2F2%29%29\". This product is:
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\n" ); document.write( "\"%28x+%2B+y%5E%281%2F2%29%29%2A%28x%5E2+%2B+2xy%5E%281%2F2%29+%2B+y%29\"
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\n" ); document.write( "Use the new rule by multiplying x times every term in the second set and then multiplying
\n" ); document.write( "\"y%5E%281%2F2%29\" by everything in the second set and you get:
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\n" ); document.write( "\"x%5E3+%2B+2x%5E2y%5E%281%2F2%29+%2B+xy+%2B+x%5E2y%5E%281%2F2%29%2B+2xy+%2B+y%5E%283%2F2%29\"
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\n" ); document.write( "Note that \"y%5E%281%2F2%29%2Ay+=+y%5E%281%2F2%29%2Ay%5E%282%2F2%29+=+y%5E%283%2F2%29\". Note also that you have some terms
\n" ); document.write( "(a couple of sets) that can be combined. After like terms are combined the answer is:
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\n" ); document.write( "\"x%5E3+%2B+3x%5E2y%5E%281%2F2%29+%2B+3xy+%2B+y%5E%283%2F2%29\"
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\n" ); document.write( "That's the answer. Hope this helps to clarify the problem for you. I noticed that in this
\n" ); document.write( "problem the formula translator clips a little bit off the tops of the numerators in the
\n" ); document.write( "exponents. Look carefully. In some cases the exponents are 1/2 and in others 3/2, but
\n" ); document.write( "you should be able to tell the difference. Sorry about that.
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