document.write( "Question 85028: Please help me solve this equation:
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document.write( "the quantity of x plus the square root of y..cubed
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document.write( "i'm not sure how to write it on the computer--
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document.write( "(x + square root y)^3
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document.write( "i know that i should separate it all out, but how do you foil a cubed equation? \n" );
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Algebra.Com's Answer #61277 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Two lessons in here. This will probably be better to work with if you replace the square \n" ); document.write( "root sign with its equivalent exponent. Remember that raising something to the (1/2) power \n" ); document.write( "is the same as taking the square root of it. So let's replace the square root of y with the \n" ); document.write( "quantity \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Next let's think about what is going on when you use the FOIL method. The term FOIL is \n" ); document.write( "just a memory jogger to help you remember what you can do to multiply two quantities \n" ); document.write( "that have two terms in each quantity. Let's take a little time to think about what you \n" ); document.write( "are doing when you \"FOIL\". Suppose you have the two terms: \n" ); document.write( ". \n" ); document.write( "(a + b)*(c + d) \n" ); document.write( ". \n" ); document.write( "If you FOIL them you get (a*c)+(a*d)+(b*c)+(b*d). Now I'm going to ask you to look at \n" ); document.write( "what you did. You took the first term in the first set of parentheses and you used it \n" ); document.write( "to multiply both terms in the second set. Then you took the second term in the first set \n" ); document.write( "of parentheses and you used it to multiply both terms in the second set. No magic there, \n" ); document.write( "but you lose sight of what you are doing by saying Firsts, Outsides, Insides, Lasts. \n" ); document.write( ". \n" ); document.write( "Now I'm going to propose something very similar to FOIL, but one set of parentheses \n" ); document.write( "will contain three terms. Suppose you have: \n" ); document.write( ". \n" ); document.write( "(a + b)*(c + d + e) \n" ); document.write( ". \n" ); document.write( "How do you do that? FOIL doesn't apply does it? Well, you just use a process similar to \n" ); document.write( "the one I suggested in the first case. Take the first term in the first set of parentheses \n" ); document.write( "(that is the term \"a\") and you multiply it by all three terms in the second set so that you \n" ); document.write( "get ac + ad + ae. Then you take the second term in the first set (that term is \"b\") and \n" ); document.write( "you multiply it by all three terms in the second set and you get bc + bd + be. Then you \n" ); document.write( "combine the two sets of answers to get ac + ad + ae + bc + bd + be. And you can use the \n" ); document.write( "same process for other problems. Take the terms one at a time from the first set of parentheses \n" ); document.write( "and multiply them by each of the terms in the second set. When you are finished with all \n" ); document.write( "the terms from the first set of parentheses, add all the answers together to get the whole \n" ); document.write( "product. \n" ); document.write( ". \n" ); document.write( "To me, it's easier to remember that method that FOIL, and it works for all sorts of products ... \n" ); document.write( "even ones such as (a + b + c + d)*(e + f + g + h + i) \n" ); document.write( ". \n" ); document.write( "For this example you would take a and multiply it by all 5 terms in the second set, then \n" ); document.write( "take b and multiply it by all 5, then take c and do the same, then take d and also do \n" ); document.write( "the same. When you get through with all those just add them up and you have the answer. \n" ); document.write( "Try doing that with FOIL ... \n" ); document.write( ". \n" ); document.write( "OK. Back to your problem. We said that we would substitute \n" ); document.write( "of y and the problem would, therefore, become: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "I think you were on the right track thinking that you could split this into: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "which would be the same as cubing it. Then you would take the first two terms and FOIL \n" ); document.write( "them to get the square of \n" ); document.write( "to get the answer. \n" ); document.write( ". \n" ); document.write( "So let's multiply the first two terms: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Multiplying the x times all the terms in the second set of parentheses and then doing the same \n" ); document.write( "for multiplying the \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Note that \n" ); document.write( "terms in the middle. As a result the product of the first two terms is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Now you need to multiply that again by \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Use the new rule by multiplying x times every term in the second set and then multiplying \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Note that \n" ); document.write( "(a couple of sets) that can be combined. After like terms are combined the answer is: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "That's the answer. Hope this helps to clarify the problem for you. I noticed that in this \n" ); document.write( "problem the formula translator clips a little bit off the tops of the numerators in the \n" ); document.write( "exponents. Look carefully. In some cases the exponents are 1/2 and in others 3/2, but \n" ); document.write( "you should be able to tell the difference. Sorry about that. \n" ); document.write( " |