document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993516>Question 993516</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find an equation of the line passing through point (-10, 3), and perpendicular to the line 2y+5x= 0, and express the result in slope intercept form.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612766 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Slope of the line 2y+5x=0 is <BR>\n" );
document.write( "2y=-5x<BR>\n" );
document.write( "y=-5x/2.  <BR>\n" );
document.write( "The line perpendicular to that has a slope of 2/5, the negative reciprocal of the above slope.<BR>\n" );
document.write( "now use point slope formula<BR>\n" );
document.write( "y-y1=(2/5)(x-x1)<BR>\n" );
document.write( "y-3=(2/5)(x+10) (watch sign here)<BR>\n" );
document.write( "y-3=2x/5+4<BR>\n" );
document.write( "y=(2/5)x+7<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-5x%2F2%29%2C%282x%2F5%29%2B7%29 ALIGN=MIDDLE  ALT=\"graph%28300%2C300%2C-10%2C10%2C-10%2C10%2C%28-5x%2F2%29%2C%282x%2F5%29%2B7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );