document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993511>Question 993511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the third of four consecutive odd integers given that the sum of the first two integers if four times the larger </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612763 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612763\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Find the third of four consecutive odd integers given that the sum of the first two integers is four times the larger.<BR>\n" );
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document.write( "1st:: 2x-3<BR>\n" );
document.write( "2nd:: 2x-1<BR>\n" );
document.write( "3rd:: 2x+1<BR>\n" );
document.write( "4th:: 2x+3\r<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "(2x-3)+(2x-1) = 4(2x+3)<BR>\n" );
document.write( "4x-4 = 8x+12<BR>\n" );
document.write( "4x = -16<BR>\n" );
document.write( "x = -4<BR>\n" );
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document.write( "3rd = 2x+1 = -7<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );