document.write( "Question 993477: Find the value of x that minimises \r
\n" ); document.write( "\n" ); document.write( "y = 16x^2 + 1800/x\r
\n" ); document.write( "\n" ); document.write( "for positive x\r
\n" ); document.write( "\n" ); document.write( "So I know I need to differentiate, but I am not sure where to go from there?\r
\n" ); document.write( "\n" ); document.write( "32x - (1800/x^2)\r
\n" ); document.write( "\n" ); document.write( "I need:\r
\n" ); document.write( "\n" ); document.write( "How many critical numbers does y have, for positive x?\r
\n" ); document.write( "\n" ); document.write( "What is the nature of the critical number of the previous part?
\n" ); document.write( "Enter m for minimum, M for maximum or i for a horizontal point of inflection.\r
\n" ); document.write( "\n" ); document.write( "Give the exact value of the x that minimises y for positive x.
\n" ); document.write( "x (at minimum) =\r
\n" ); document.write( "\n" ); document.write( "Now give the value approximately as a 2 decimal place decimal. Now, give the approximate value (as a 2 decimal place decimal) of the x that minimises y for positive x.
\n" ); document.write( "x (at minimum) ≈\r
\n" ); document.write( "\n" ); document.write( "THANK YOU
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Algebra.Com's Answer #612759 by rothauserc(4718)\"\" \"About 
You can put this solution on YOUR website!
y = 16x^2 + 1800/x
\n" ); document.write( "dy/dx = 32x -(1800/x^2)
\n" ); document.write( "to find min x for positive x set dy/dx = 0
\n" ); document.write( "32x -(1800/x^2) = 0
\n" ); document.write( "multiply both sides of = by x^2
\n" ); document.write( "32x^3 - 1800 = 0
\n" ); document.write( "32x^3 = 1800
\n" ); document.write( "x = (15/2)^(2/3)
\n" ); document.write( "for positive x, x is a local minimum
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\n" ); document.write( "x(at minimum) = (15/2)^(2/3)
\n" ); document.write( "x(at minimum) = 3.831547162 approx 3.83
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\n" ); document.write( "here is the graph of y = 16x^2 + 1800/x to help visualize this problem
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-5%2C+5%2C+-4000%2C+4000%2C+%2816%2Ax%5E2%29+%2B+1800%2Fx%29+\"
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