document.write( "Question 993477: Find the value of x that minimises \r
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document.write( "y = 16x^2 + 1800/x\r
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document.write( "for positive x\r
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document.write( "So I know I need to differentiate, but I am not sure where to go from there?\r
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document.write( "32x - (1800/x^2)\r
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document.write( "I need:\r
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document.write( "How many critical numbers does y have, for positive x?\r
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document.write( "What is the nature of the critical number of the previous part?
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document.write( "Enter m for minimum, M for maximum or i for a horizontal point of inflection.\r
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document.write( "Give the exact value of the x that minimises y for positive x.
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document.write( "x (at minimum) =\r
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document.write( "Now give the value approximately as a 2 decimal place decimal. Now, give the approximate value (as a 2 decimal place decimal) of the x that minimises y for positive x.
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document.write( "x (at minimum) ≈\r
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document.write( "THANK YOU \n" );
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Algebra.Com's Answer #612759 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! y = 16x^2 + 1800/x \n" ); document.write( "dy/dx = 32x -(1800/x^2) \n" ); document.write( "to find min x for positive x set dy/dx = 0 \n" ); document.write( "32x -(1800/x^2) = 0 \n" ); document.write( "multiply both sides of = by x^2 \n" ); document.write( "32x^3 - 1800 = 0 \n" ); document.write( "32x^3 = 1800 \n" ); document.write( "x = (15/2)^(2/3) \n" ); document.write( "for positive x, x is a local minimum \n" ); document.write( "******************************************* \n" ); document.write( "x(at minimum) = (15/2)^(2/3) \n" ); document.write( "x(at minimum) = 3.831547162 approx 3.83 \n" ); document.write( "******************************************* \n" ); document.write( "here is the graph of y = 16x^2 + 1800/x to help visualize this problem \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |