document.write( "Question 993509: In geometry, two angles that sum to 90◦ are called complementary angles. If the second of two complementary angles is 57 degrees larger than 2 times the first angle, find the degree measure of both angles. \n" ); document.write( "

Algebra.Com's Answer #612754 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "let angles be $\"alpha\"$ and $\"beta\"$ \r
\n" ); document.write( "\n" ); document.write( "if $\"alpha\"$ and $\"beta\"$ are complementary angles, then $\"alpha%2Bbeta=90\"$ °\r
\n" ); document.write( "\n" ); document.write( "if the second of two complementary angles is $\"beta\"$ is $\"57\"$ ° larger than $\"2\"$ times the first angle $\"alpha\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"beta=2alpha%2B57\"$ °........substitute it in $\"alpha%2Bbeta=90\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"alpha%2B2alpha%2B57=90\"$ °.............solve for $\"alpha\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3alpha=90-57\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"3alpha=33\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"alpha=33%2F3\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28alpha=11%29\"$ °\r
\n" ); document.write( "\n" ); document.write( "go to $\"beta=2alpha%2B57\"$ ° substitute $\"11\"$ for $\"alpha\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"beta=2%2A11%2B57\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"beta=22%2B57\"$ °\r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28beta=79%29\"$ °\r
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\n" ); document.write( "\n" ); document.write( "so your angles are: $\"highlight%2811%29\"$ ° and $\"highlight%2879%29\"$ °\r
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