document.write( "Question 993342: The area of a rectangle is six square feet. The rectangle's length is two feet more than three times the width. Find the rectangle's width (in feet) rounded to two decimal places \n" ); document.write( "
Algebra.Com's Answer #612679 by macston(5194)\"\" \"About 
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\n" ); document.write( "W=width; L=length=3W+2
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\n" ); document.write( "A=LW
\n" ); document.write( "A=(3W+2)(W)
\n" ); document.write( "6=3W^2+2W
\n" ); document.write( "0=3W^2+2W-6
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aW%5E2%2BbW%2Bc=0\" (in our case \"3W%5E2%2B2W%2B-6+=+0\") has the following solutons:
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\n" ); document.write( " \"W%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%282%29%5E2-4%2A3%2A-6=76\".
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\n" ); document.write( " Discriminant d=76 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-2%2B-sqrt%28+76+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"W%5B1%5D+=+%28-%282%29%2Bsqrt%28+76+%29%29%2F2%5C3+=+1.11963298118022\"
\n" ); document.write( " \"W%5B2%5D+=+%28-%282%29-sqrt%28+76+%29%29%2F2%5C3+=+-1.78629964784689\"
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\n" ); document.write( " Quadratic expression \"3W%5E2%2B2W%2B-6\" can be factored:
\n" ); document.write( " \"3W%5E2%2B2W%2B-6+=+3%28W-1.11963298118022%29%2A%28W--1.78629964784689%29\"
\n" ); document.write( " Again, the answer is: 1.11963298118022, -1.78629964784689.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B2%2Ax%2B-6+%29\"

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\n" ); document.write( "W=1.12 feet
\n" ); document.write( "ANSWER: The width is 1.12 feet
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\n" ); document.write( "CHECK:
\n" ); document.write( "L=3W+2=3(1.12)+2=3.36+2=5.36
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\n" ); document.write( "A=LW
\n" ); document.write( "6=(5.36)(1.12)
\n" ); document.write( "6=6\r
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