document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993251>Question 993251</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the measure of the third angle of the triangle is 15 degree more than the measure of either of the other two angles, find the measure of each angle of the triangle. Recall that the sum of the measures of the angles of a triangle is 180 degree\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612651 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a=measure of each of the other angles<BR>\n" );
document.write( "a+15=measure of third angle<BR>\n" );
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document.write( "a+a+a+15=180<BR>\n" );
document.write( "3a=165<BR>\n" );
document.write( "a=55<BR>\n" );
document.write( "third angle=a+15degrees=55degrees+15 degrees=70 degrees<BR>\n" );
document.write( "The first 2 angles each measure 55 degrees and the third angle is 70 degrees.<BR>\n" );
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