document.write( "Question 993349: My brother is 5years older than I am in 7years time I will be 3quarters of his age.\r
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document.write( "What is my current age? \n" );
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Algebra.Com's Answer #612614 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "x=your current age; B=brother's age=x+5 \n" ); document.write( ". \n" ); document.write( "x+7=(0.75)(B+7) \n" ); document.write( "x+7=(0.75)((x+5)+7) \n" ); document.write( "x+7=(0.75)(x+12) \n" ); document.write( "x+7=0.75x+9 \n" ); document.write( "0.25x=2 \n" ); document.write( "x=8 \n" ); document.write( "ANSWER: You are currently 8 years old. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "B=x+5=8+5=13 . Brother is 13 years old. \n" ); document.write( "x+7=(0.75)(B+7) \n" ); document.write( "8+7=(0.75)(13+7) \n" ); document.write( "15=(0.75)(20) \n" ); document.write( "15=15\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |