document.write( "Question 993293: The doubling period of a bacterial population is 20 minutes. At time t=90 minutes, the bacterial population was 50000.\r
\n" ); document.write( "\n" ); document.write( " What was the initial population at time t=0 ? \r
\n" ); document.write( "\n" ); document.write( " Find the size of the bacterial population after 3 hours
\n" ); document.write( "*formula: p(t)=a(b)^t
\n" ); document.write( "**Note:b=1+r
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #612588 by MathTherapy(10555) $\"\"$ $\"About$

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The doubling period of a bacterial population is 20 minutes. At time t=90 minutes, the bacterial population was 50000.\r
\n" ); document.write( "\n" ); document.write( " What was the initial population at time t=0 ? \r
\n" ); document.write( "\n" ); document.write( " Find the size of the bacterial population after 3 hours
\n" ); document.write( "*formula: p(t)=a(b)^t
\n" ); document.write( "**Note:b=1+r
\n" ); document.write( "

r, or growth rate = .035264924 ≈ 3.526%, per minute
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document.write( "Initial population at time = 0 minutes: 2,209.708691 ≈ 
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document.write( "Population at time = 3 hours (180 minutes): 1,131,370.8499 ≈  \n" );
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