document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=85000>Question 85000</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0131432435/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Given f(x) = 2x^2 - 3x + 4, find the following:\r<BR>\n" );
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document.write( "f(4)\r<BR>\n" );
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document.write( "f(-3)\r<BR>\n" );
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document.write( "f(0) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #61255 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=61255\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = 2x^2 - 3x + 4 [substitute each number for x and solve the equation:<BR>\n" );
document.write( "f(4)= 2(4)^2 - 3(4) + 4 <BR>\n" );
document.write( "f(4)= 32-12+4<BR>\n" );
document.write( "f(4)=20+4<BR>\n" );
document.write( "f(4)=24<BR>\n" );
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document.write( "f(-3)= 2(-3)^2 - 3(-3) + 4 <BR>\n" );
document.write( " f(-3)= 2(9) +9 + 4<BR>\n" );
document.write( "f(-3)= 18 + 9 + 4<BR>\n" );
document.write( "f(-3)= 27+4<BR>\n" );
document.write( "f(-3)= 31<BR>\n" );
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document.write( "f(0) = 2(0)^2 - 3(0) + 4 <BR>\n" );
document.write( "f(0) = 0- 0 + 4 <BR>\n" );
document.write( "f(0)=4 </SPAN>\n" );
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