document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=993223>Question 993223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A silversmith mixed 35 g of an 80% silver alloy with 40 g of a 25% silver alloy. What is the percent concentration of the resulting alloy? (Round your answer to one decimal place.) <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #612546 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=612546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 35+40= 75 Total of all silver alloy<BR>\n" );
document.write( "35/75= 46.7% of the total silver alloy is 80% silver alloy<BR>\n" );
document.write( "40/75= 53.3% of the total silver alloy is 25% silver alloy\r<BR>\n" );
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document.write( "(0.467 x 0.8)+(0.533 x 0.25)= 0.374+0.133= 0.507= 50.7% is the percentage concentration of the resulting alloy. </SPAN>\n" );
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